88 lines
11 KiB
Plaintext
88 lines
11 KiB
Plaintext
{
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"nodes":[
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{"id":"9effe93fe812b3d5","type":"text","text":"风速范围 间隔点","x":160,"y":-280,"width":250,"height":60},
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{"id":"5818e7212360b063","type":"text","text":"可选是否MBC转换","x":160,"y":-140,"width":250,"height":60},
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{"id":"226774e95f4236f0","type":"text","text":"问题2 非线性，如何线性化","x":160,"y":140,"width":250,"height":60},
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{"id":"65a392a60c82cf13","type":"text","text":"问题1 动力学方程是二阶线性还是二阶非线性","x":135,"y":-15,"width":300,"height":90},
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{"id":"8c2eadcabf51301e","type":"text","text":"非线性\n$$\n\\begin{array}{r}{\\dot{\\mathbf{x}}=f(t,\\mathbf{x},\\mathbf{u})}\\\\ {\\mathbf{y}=h(t,\\mathbf{x},\\mathbf{u})}\\end{array}\n$$","x":540,"y":-37,"width":250,"height":135},
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{"id":"e3f81d5e91896a13","type":"text","text":"小扰动+回归","x":540,"y":140,"width":250,"height":60},
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{"id":"4a884b5e3feb7e40","type":"text","text":"气动力 = (K结构 + K钢化）q","x":540,"y":-220,"width":250,"height":60},
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{"id":"498cc5a9e1e188ac","type":"text","text":"fast中两个K如何求？","x":880,"y":-220,"width":250,"height":60},
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{"id":"158be82aaa1bd0b4","type":"text","text":"气动力如何求","x":880,"y":-140,"width":250,"height":60},
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{"id":"2a5628f97c424f0d","type":"text","text":"直接去掉$\\dot{q}、\\ddot{q}$项","x":1220,"y":-220,"width":250,"height":60},
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{"id":"0fbf8b3541d79def","type":"text","text":"形成新的增广矩阵，求解得到q","x":1540,"y":-220,"width":250,"height":60},
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{"id":"799124dab8c18b5d","type":"text","text":"气动+多体耦合迭代至收敛","x":880,"y":-15,"width":250,"height":60},
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{"id":"fad5bc614aaee083","type":"text","text":"q = 0 直叶片算气动力","x":1220,"y":-15,"width":250,"height":60},
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{"id":"cc8c72de61dbdb4e","type":"text","text":"算出一个变形量","x":1220,"y":98,"width":250,"height":60},
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{"id":"c88b095b542d6843","type":"text","text":"气动再计算","x":1220,"y":200,"width":250,"height":60},
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{"id":"e0c849b33a39c56e","type":"text","text":"结构再算变形量","x":1220,"y":300,"width":250,"height":60},
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{"id":"f1503269ba230604","type":"text","text":"直至变形量收敛/a a'收敛","x":1220,"y":420,"width":250,"height":60},
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{"id":"e9c01c636e40c0b3","type":"text","text":"t=0时刻改进 成 稳态增广矩阵","x":1540,"y":-15,"width":250,"height":60},
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{"id":"45421c5911e8d893","type":"text","text":"能不能算？应该可以","x":1540,"y":98,"width":250,"height":60},
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{"id":"bbcf3043979eac49","type":"text","text":"平衡状态平衡值x：---q","x":-720,"y":0,"width":250,"height":60},
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{"id":"efcf091d8aaf324d","type":"text","text":"仅考虑求A矩阵","x":-720,"y":140,"width":250,"height":60},
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{"id":"db651e5e09444ed4","type":"text","text":"Δq 求 $Δ \\dot{q}$ 再线性回归","x":-720,"y":280,"width":250,"height":60},
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{"id":"c86002941101b4b0","type":"text","text":"自由度上，其中一个做一组扰动，求瞬态的其他自由度的加速度，线性拟合，Aij","x":160,"y":420,"width":380,"height":120},
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{"id":"f264418318fe13a2","type":"text","text":"组装A矩阵","x":225,"y":620,"width":250,"height":60},
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{"id":"84420c9c180de186","type":"text","text":"A矩阵求特征值和特征向量","x":225,"y":800,"width":250,"height":80},
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{"id":"c03f206d2e22c014","type":"text","text":"设置工况点","x":-300,"y":-280,"width":250,"height":60},
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{"id":"82e0fa4b70baffed","type":"text","text":"每个工况点求稳态解","x":-300,"y":-140,"width":250,"height":60},
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{"id":"d3aa69200118cea0","type":"text","text":"小扰动求A, B, C, D","x":-300,"y":0,"width":250,"height":60},
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{"id":"f8e0af85235be889","type":"text","text":"A上做特征值、模态","x":-300,"y":140,"width":250,"height":60},
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{"id":"03f26deb8603c7c3","type":"text","text":"输出哪些量","x":-300,"y":280,"width":250,"height":60},
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{"id":"3ad569bafe12c1a6","x":-425,"y":1020,"width":650,"height":60,"type":"text","text":"Maximum mode frequency to perturb and measure derivatives in the analysis, When using a multi-part blade, the whole\nblade modes are perturbed, The user may decide it is not necessary to analyse the higher freguency whole blade modes"},
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{"id":"8ca8904fa77d3fc0","x":-425,"y":1130,"width":650,"height":60,"type":"text","text":"Number of values that each state gets perturbed to either side of the equilibrium point, Larger numbers provide more\nrobustness, Smaller numbers provide faster analysis and lower memory usage."},
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{"id":"530691ed6242d413","x":-425,"y":1220,"width":650,"height":60,"type":"text","text":"Zero value states have a perturbation magnitude of this value multiplied by the absolute tolerance of the state"},
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{"id":"ef6765604030b0d2","x":-425,"y":1320,"width":650,"height":60,"type":"text","text":"The magnitude of the state perturbations relative to the absolute steady-state state values"},
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{"id":"667596ff1268005b","type":"text","text":"Maximum frequency to analyse","x":-845,"y":1020,"width":340,"height":60},
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{"id":"871eda913aa536f2","type":"text","text":"Number of perturbation points","x":-845,"y":1130,"width":340,"height":60},
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{"id":"62cc86d57a340008","type":"text","text":"Absolute tolerance perturbation scale","x":-845,"y":1220,"width":340,"height":60},
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{"id":"f0a4983cbe88dea0","type":"text","text":"State relative perturbation","x":-845,"y":1320,"width":340,"height":60},
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{"id":"4487cb5e83fd2407","x":300,"y":1020,"width":820,"height":60,"type":"text","text":"分析中扰动和测量导数的最大模态频率。当使用多段叶片时，整个叶片的模态会受到扰动，用户可能会认为没有必要分析更高频率的整个叶片模态。"},
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{"id":"66af2e27cd04234b","x":300,"y":1130,"width":820,"height":60,"type":"text","text":"每个状态在平衡点两侧扰动到的值数量，数量越大则鲁棒性越强，数量越小则分析速度越快且内存使用量越低。"},
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{"id":"be4ee34e7361d0ea","x":300,"y":1220,"width":820,"height":60,"type":"text","text":"零值状态的扰动幅度是该值乘以状态的绝对容差。"},
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{"id":"83ad7939febb40fb","x":300,"y":1320,"width":820,"height":60,"type":"text","text":"状态扰动相对于绝对稳态状态值的大小"},
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{"id":"57a77fa21396c8f3","x":1397,"y":971,"width":250,"height":60,"type":"text","text":"仅支持叶片稳态"},
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{"id":"45093d1a52b13379","x":1397,"y":1070,"width":250,"height":60,"type":"text","text":"增加其他自由度稳态计算方法"},
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{"id":"3e1714739e73cd8f","x":1780,"y":971,"width":250,"height":60,"type":"text","text":"先完成叶片的扰动"}
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