| ElasticDrive | C(q,t) DampDrive |
| {-f(q,q,t)}] ElasticDrive | andlikewise (-f(4,q,t) |
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| .............................................. | IDampDrive |
| -DTTorSpr · qDrTr | -DTTorDmp·qDrTr |
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| ··.............................................·.. | .·.................................................·. |
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Similar to the generator and HSS brake, the mechanical friction torque applied to the high speed shaft is applied equally and oppositely to the structure that furls with the rotor. Thus,
类似于发电机和HSS制动器，施加到高速轴上的机械摩擦扭矩，以相等且相反的方式作用于与转子一同旋转的结构上。因此，
F $=\int_{0}^{\varepsilon}\!\omega_{G e i z}^{G}\cdot M_{\mathit{c B F r i c}}^{G}\quad\mathit{f o r}\quad r=G e d z\qquad\qquad\mathrm{where}\qquad\qquad M_{\mathit{G B F r i c}}^{G}=-\frac{T^{G B F r i c}\left(\ddot{q},\dot{q},\dot{q}\right)}{G B R a t i o\cdot G e^{G B F r i c}}\,,$ GBFric
where, from a free-body diagram of the high and low-speed shafts, it is easily seen that the friction torque applied on the LSS upon the gearbox entrance, $T^{G B F r i c}\left(\ddot{q},\dot{q},q,t\right)$ , is always positive in value and equal to:
从高速轴和低速轴的受力图上可以清楚地看到，作用于低速轴进入变速箱处的摩擦转矩，$T^{G B F r i c}\left(\ddot{q},\dot{q},q,t\right)$，其值始终为正，且等于：
$$
,t\bigr)\mathop{=}^{\sim}\biggl[G e n l n e r\cdot G B R a t i o^{2}\cdot\ddot{q}_{G e d z}+G e n D i r\cdot G e n l n e r\cdot G B R a t i o^{E}a^{R}\cdot c_{I}\biggr]\cdot\biggl[\frac{I}{G B o x E/f^{S I G}}\Bigl(G B R a t i o\cdot\dot{q}_{G e d z},t\Bigr)+G B R a t i o\cdot T^{B r a k e}\left(t\right)\biggr]^{2}.
$$
Thus,
$\left.F_{r}\right|_{G B F r i c}=\left\{\begin{array}{l l}{-T^{G B F r i c}\left(\ddot{q},\dot{q},q,t\right)}&{f o r~~r=G e A z}\\ {0}&{o t h e r w i s e}\end{array}\right.$
or, $\cdot\!\!\!\mid_{G B F r i c}=\left\{\!\!\!\left[\!\!\begin{array}{c}{{G e n I n e r\cdot G B R a t i o^{\prime}\cdot\ddot{q}_{G e d z}+G e n D i r\cdot G e n I n e r\cdot G B R a t i o^{\varepsilon}a^{R}\cdot c_{I}}}\\ {{+G B R a t i o\cdot T^{G e n}\left(G B R a t i o\cdot\dot{q}_{G e d z},t\right)+G B R a t i o\cdot T^{B r a k e}\left(t\right)}}\end{array}\!\!\right]\!:\left[\!\!\frac{1}{G B o x}\!\!\!\right]\!:=\!\!\!\left[\!\!\begin{array}{c}{{\Psi_{0}}}\\ {{G e n I}}\\ {{\Psi_{1}}}\end{array}\!\!\!\right]\!\!:=\!\!\!\left[\!\!\begin{array}{c}{{\Psi_{0}}}\\ {{G e n I}}\\ {{\Psi_{2}}}\end{array}\!\!\!\right]\!\!.$ 1
F GBoxEffSIGN (LSShftTq) for r=GeAz otherwise