vault backup: 2025-09-11 17:10:27

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yize 2025-09-11 17:10:28 +08:00
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commit cd99ea55f0

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@ -354,11 +354,36 @@ $$
F_{r}\Big|_{G e n}=\left\{\begin{array}{l l}{\left(G e n D i r\cdot G B R a t i o\cdot c_{I}\right)\cdot\left[-G e n D i r\cdot T^{G e n}\left(G B R a t i o\cdot\dot{q}_{G e d z},t\right)c_{I}\right]}&{f o r\;\;\;r=G e n D i r}\\ {0}&{o t h e r w i s e}\end{array}\right.
$$
Or since $G e n D i r^{2}=I$ ,
Or since $G e n D i r^{2}=1$ ,
# Thus, $\left[C(q,t)\right]_{G e n}=0$
$$
<html><body><table><tr><td rowspan="14">{-f(g,q,t)}</td></tr><tr><td></td></tr><tr><td></td></tr><tr><td></td></tr><tr><td></td></tr><tr><td></td></tr><tr><td></td></tr><tr><td></td></tr><tr><td></td></tr><tr><td></td></tr><tr><td></td></tr><tr><td>Gen</td></tr><tr><td>GBRatio·T Gen GBRatio·qGeAz'</td></tr><tr><td></td></tr><tr><td></td></tr><tr><td></td></tr><tr><td></td></tr><tr><td></td></tr><tr><td></td></tr><tr><td></td></tr><tr><td></td></tr><tr><td></td></tr></table></body></html>
F_r \Big|_{Gen} = \begin{cases}
-GRRatio \cdot T^{Gen} (GRRatio \cdot \dot{q}_{GeAz}, t) & \text{for } r = GeAz \\
0 & \text{otherwise}
\end{cases}
$$
Thus, $\left[C(q,t)\right]_{G e n}=0$
$$
[C(\mathbf{q},t)]_{Gen} = 0
$$
$$
\{-f(\dot{\mathbf{q}},\mathbf{q},t)\}_{Gen} = \left[
\begin{array}{c}
\vdots \\
0 \\
-GBRatio \cdot T^{Gen} (GRRatio \cdot \dot{q}_{GeAz}, t) \\
0 \\
\vdots
\end{array}
\right]
$$
Similarly, the mechanical torque applied to the high-speed shaft from the high-speed shaft brake is applied equally and oppositely to the structure that furls with the rotor. Thus,
同样地,从高速轴制动器施加到高速轴上的机械扭矩,也会以相等且相反的方式作用于与转子一同回转的结构上。因此,
@ -371,13 +396,22 @@ $$
F_{r}\bigr|_{B r a k e}=\left\{\begin{array}{l l}{-G B R a t i o\cdot T^{B r a k e}\left(t\right)}&{f o r\;\;\;r=G e A z}\\ {O}&{o t h e r w i s e}\end{array}\right.
$$
# Thus,
Thus,
$$
[C(\mathbf{q},t)]_{Brake} = 0
$$
$$
\left[C(q,t)\right]\Bigr|_{B r a k e}={\cal O}
$$
<html><body><table><tr><td rowspan="14">(-f(4,q,t) Brake</td></tr><tr><td></td></tr><tr><td></td></tr><tr><td></td></tr><tr><td></td></tr><tr><td></td></tr><tr><td></td></tr><tr><td></td></tr><tr><td></td></tr><tr><td></td></tr><tr><td></td></tr><tr><td></td></tr><tr><td>GBRatio·TBrake</td></tr><tr><td></td></tr><tr><td></td></tr><tr><td></td></tr><tr><td></td></tr><tr><td></td></tr><tr><td></td></tr><tr><td></td></tr><tr><td></td></tr><tr><td></td></tr></table></body></html>
\{-f(\dot{\mathbf{q}},\mathbf{q},t)\}_{Brake} = \left[
\begin{array}{c}
\vdots \\
0 \\
-GBRatio \cdot T^{Brake}(t) \\
0 \\
\vdots
\end{array}
\right]
$$
If the translational inertia of the drivetrain is assumed to be incorporated into that of the structure that furls with the rotor, then the high-speed shaft generator inertia generalized force is as follows:
如果假设动能惯性由驱动系传递至随转子摆动的结构部分,则高速轴发电机惯性概括力如下: