From 948d03508344cc3267d15abd0d78408772350bda Mon Sep 17 00:00:00 2001
From: aGYZ <5722745+agyz@user.noreply.gitee.com>
Date: Thu, 28 Aug 2025 08:10:14 +0800
Subject: [PATCH] vault backup: 2025-08-28 08:10:14

---
 ...822_090314__[[CASEstab_theory_manual]]整篇文稿的逻辑是什么.md | 1 +
 1 file changed, 1 insertion(+)

diff --git a/copilot-conversations/20250822_090314__[[CASEstab_theory_manual]]整篇文稿的逻辑是什么.md b/copilot-conversations/20250822_090314__[[CASEstab_theory_manual]]整篇文稿的逻辑是什么.md
index d8f8c9f..1ec3e9b 100644
--- a/copilot-conversations/20250822_090314__[[CASEstab_theory_manual]]整篇文稿的逻辑是什么.md
+++ b/copilot-conversations/20250822_090314__[[CASEstab_theory_manual]]整篇文稿的逻辑是什么.md
@@ -173,6 +173,7 @@ $$
 \mathbf{r}_{1,b,n} = \sum_{p=0}^{P+3}\left(\mathbf{r}_{o,b,n,p} + x\,\mathbf{r}_{x,b,n,p} + y\,\mathbf{r}_{y,b,n,p}\right)\zeta^{p}
 $$
 This brilliant step separates the position vector into parts that depend only on the nodal DOFs and the lengthwise coordinate $\zeta$ (the $\mathbf{r}_{o,x,y}$ vectors), and parts that depend on the cross-section coordinates ($x, y$). This is the key that unlocks the integration in the next stage.
+
 最终目标是找到叶片中任何质点的位置矢量 $\mathbf{r}$，因为所有惯性力都由此导出（参见式 1.8）。
 
 **1.1. 宏观视角：子结构位置（式 1.12）**