obsidian_backup/线性化求解器/计算流程框架.canvas

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		{"id":"c03f206d2e22c014","type":"text","text":"设置工况点","x":-200,"y":-280,"width":250,"height":60},
		{"id":"9effe93fe812b3d5","type":"text","text":"风速范围 间隔点","x":160,"y":-280,"width":250,"height":60},
		{"id":"82e0fa4b70baffed","type":"text","text":"每个工况点求稳态解","x":-200,"y":-140,"width":250,"height":60},
		{"id":"d3aa69200118cea0","type":"text","text":"小扰动求A, B, C, D","x":-200,"y":0,"width":250,"height":60},
		{"id":"f8e0af85235be889","type":"text","text":"A上做特征值、模态","x":-200,"y":140,"width":250,"height":60},
		{"id":"5818e7212360b063","type":"text","text":"可选是否MBC转换","x":160,"y":-140,"width":250,"height":60},
		{"id":"03f26deb8603c7c3","type":"text","text":"输出哪些量","x":-200,"y":280,"width":250,"height":60},
		{"id":"226774e95f4236f0","type":"text","text":"问题2 非线性，如何线性化","x":160,"y":140,"width":250,"height":60},
		{"id":"65a392a60c82cf13","type":"text","text":"问题1 动力学方程是二阶线性还是二阶非线性","x":135,"y":-15,"width":300,"height":90},
		{"id":"8c2eadcabf51301e","type":"text","text":"非线性\n$$\n\\begin{array}{r}{\\dot{\\mathbf{x}}=f(t,\\mathbf{x},\\mathbf{u})}\\\\ {\\mathbf{y}=h(t,\\mathbf{x},\\mathbf{u})}\\end{array}\n$$","x":540,"y":-37,"width":250,"height":135},
		{"id":"e3f81d5e91896a13","type":"text","text":"小扰动+回归","x":540,"y":140,"width":250,"height":60},
		{"id":"4a884b5e3feb7e40","type":"text","text":"气动力 = (K结构 + K钢化）q","x":540,"y":-220,"width":250,"height":60},
		{"id":"498cc5a9e1e188ac","type":"text","text":"fast中两个K如何求？","x":880,"y":-220,"width":250,"height":60},
		{"id":"158be82aaa1bd0b4","type":"text","text":"气动力如何求","x":880,"y":-140,"width":250,"height":60},
		{"id":"2a5628f97c424f0d","type":"text","text":"直接去掉$\\dot{q}、\\ddot{q}$项","x":1220,"y":-220,"width":250,"height":60},
		{"id":"0fbf8b3541d79def","x":1540,"y":-220,"width":250,"height":60,"type":"text","text":"形成新的增广矩阵，求解得到q"},
		{"id":"799124dab8c18b5d","x":880,"y":-15,"width":250,"height":60,"type":"text","text":"气动+多体耦合迭代至收敛"},
		{"id":"fad5bc614aaee083","x":1220,"y":-15,"width":250,"height":60,"type":"text","text":"q = 0 直叶片算气动力"},
		{"id":"cc8c72de61dbdb4e","x":1220,"y":98,"width":250,"height":60,"type":"text","text":"算出一个变形量"},
		{"id":"c88b095b542d6843","x":1220,"y":200,"width":250,"height":60,"type":"text","text":"气动再计算"},
		{"id":"e0c849b33a39c56e","x":1220,"y":300,"width":250,"height":60,"type":"text","text":"结构再算变形量"},
		{"id":"f1503269ba230604","x":1220,"y":420,"width":250,"height":60,"type":"text","text":"直至变形量收敛/a a'收敛"},
		{"id":"e9c01c636e40c0b3","x":1540,"y":-15,"width":250,"height":60,"type":"text","text":"t=0时刻改进 成 稳态增广矩阵"},
		{"id":"45421c5911e8d893","x":1540,"y":98,"width":250,"height":60,"type":"text","text":"能不能算？应该可以"}
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